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Comments

Jordan C

I've been having troubles with finding the derivatives of equations with e to a negative exponent, I'm not sure why though. I'll be in at lunch for help for the next few days...
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Mr. Shaddick: Are you remember to the chain rule with the exponent? If the exponent is -x, by applying the chain rule, you will have to multiply e^-x by -1 (the d/dx of -x). I hope that helps.

Jordan C

I'm also having a bit of trouble with ln questions with square roots in them, or larger equations in place of x. And equations like ln 6x/ln 2x. I think I'm grasping that that equation can be written as log2 6 but I don't think that helps me solve the problem.
Mr. Shaddick: Have you tried using the quotient rule?

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Can you post today work may 11 2009
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Mr. Shaddick: I'm pretty sure that I assigned 9ace and 11-17 from last day's handout.

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